An electrical appliance has a rating of $5 kW, 200 V$ . What should be the minimum current rating of the fuse to be used with the appliance?

5 A

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15 A

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20 A

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26 A

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Solution

The correct option is D $26 A$
Fuse wire is made thin so that when current exceeds the rating of the fuse, It melts and breaks the circuit.
$P = V I$
For $V = 200 V, P = 5000 W$ (Given)
$I = \frac{P}{V} = 25 A$
So, current rating of fuse should be at least $25 A$ .

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An electrical appliance has a rating of 5 kW, 200V. What should be the minimum current rating of the fuse to be used with the appliance?

The correct option is D 26 AFuse wire is made thin so that when current exceeds the rating of the fuse, It melts and breaks the circuit. P=VI For V=200 V, P=5000 W (Given) I=PV=25 A So, current rating of fuse should be at least 25 A.

An electrical appliance has a rating of $5 kW, 200 V$ . What should be the minimum current rating of the fuse to be used with the appliance?

The correct option is D $26 A$
Fuse wire is made thin so that when current exceeds the rating of the fuse, It melts and breaks the circuit.
$P = V I$
For $V = 200 V, P = 5000 W$ (Given)
$I = \frac{P}{V} = 25 A$
So, current rating of fuse should be at least $25 A$ .