Question

An electrical appliance of 500 W is used for 5 hours per day. Energy consumed in 30 days will be:

• A. 2.5 k W h
• B. 25 k W h
• C. 75 k W h
• D. None of these

Answer 1

Answer: (C)

75 k W h

Given: Power = 500 W = $\frac{500}{1000}=0.5kW$
Time of usage per day $=5hours$
Number of days $30days$
Energy consumed = $power\times time\times numberofdays$.

$Energyconsumed=0.5kW\times 5\times 30$
$Energyconsumed=75kWh$.