An electrical cable having a resistance of 0-2 - delivers 10 kW at 200 V DC to a factory- What is the efficiency of transmission-

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Question

An electrical cable having a resistance of $0.2 Ω$ delivers $10 k W$ at $200 V$ DC to a factory. What is the efficiency of transmission?

65%

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75%

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85%

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95%

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Solution

The correct option is D 95%
Power $P = V I$
$\Rightarrow I = \frac{P}{V} = \frac{10 \times 10^{3}}{200} = 50 A$
$∴$ Power loss $= I^{2} R = {(50)}^{2} \times (0.2) = 500 W$
Therefore, efficiency of transmission $= \frac{10000 \times 100}{10000 + 500}$
$= 95.23$ % $= 95$ % (approx).

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An electrical cable having a resistance of 0.2Ω delivers 10kW at 200V DC to a factory. What is the efficiency of transmission?

The correct option is D 95%Power P=VI⇒I=PV=10×103200=50A∴ Power loss =I2R=(50)2×(0.2)=500WTherefore, efficiency of transmission =10000×10010000+500 =95.23% =95% (approx).

An electrical cable having a resistance of $0.2 Ω$ delivers $10 k W$ at $200 V$ DC to a factory. What is the efficiency of transmission?

The correct option is D 95%
Power $P = V I$
$\Rightarrow I = \frac{P}{V} = \frac{10 \times 10^{3}}{200} = 50 A$
$∴$ Power loss $= I^{2} R = {(50)}^{2} \times (0.2) = 500 W$
Therefore, efficiency of transmission $= \frac{10000 \times 100}{10000 + 500}$
$= 95.23$ % $= 95$ % (approx).