An electrical power line- having a total resistance of 2 - - delivers 1 kW at 220 V- The efficiency of the transmission line is approximately

Given: Power, P=1 kW=1000 W R=2 Ω, V=220 V Current, I=PV=1000220 Power lost is nbsp;P_loss=I^2R= (1000220)^2 × 2 ∴ Efficiency =10001000+P_loss× 100=96 % ...

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Standard VIII

Physics

Fuse

An electrical...

Question

An electrical power line, having a total resistance of $2 Ω$ , delivers $1 kW$ at $220 V$ . The efficiency of the transmission line is approximately

72 %

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91 %

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85 %

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96 %

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Solution

The correct option is D $96 %$
Given:
Power, $P = 1 kW = 1000 W$
$R = 2 Ω, V = 220 V$

Current, $I = \frac{P}{V} = \frac{1000}{220}$

Power lost is $P_{loss} = I^{2} R = {(\frac{1000}{220})}^{2} \times 2$

$∴$ Efficiency $= \frac{1000}{1000 + P_{loss}} \times 100 = 96 %$

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An electrical power line, having a total resistance of 2 Ω , delivers 1 kW at 220 V. The efficiency of the transmission line is approximately

The correct option is D 96 %Given: Power, P=1 kW=1000 W R=2 Ω,V=220 V Current, I=PV=1000220 Power lost is Ploss=I2R=(1000220)2×2 ∴ Efficiency =10001000+Ploss×100=96 %

An electrical power line, having a total resistance of $2 Ω$ , delivers $1 kW$ at $220 V$ . The efficiency of the transmission line is approximately

The correct option is D $96 %$
Given:
Power, $P = 1 kW = 1000 W$
$R = 2 Ω, V = 220 V$

Current, $I = \frac{P}{V} = \frac{1000}{220}$

Power lost is $P_{loss} = I^{2} R = {(\frac{1000}{220})}^{2} \times 2$

$∴$ Efficiency $= \frac{1000}{1000 + P_{loss}} \times 100 = 96 %$