Question

An electrical shopkeeper purchases bulbs fromthree manufacturers A, B, C. He purchases $25$%of his stock from A, $45$% from B and $30$% from C.In the past purchases he found $2$% of Cs bulbs,1% of Bs bulbs, 1% of As bulbs were defective.Assuming that, the shopkeeper chooses a bulband found it to be defective
LIST-I LIST-II
A) The probability of choosing 1) 0.0025
A and purchasing a defective
bulb from it is
B) The probability of choosing 2) 0.0045
B and purchasing a defective
bulb from it is
C) The probability of choosing 3) 0.0060
C and purchasing a defective
bulb from it is
D) The probability that the 4) 0.65
defective bulb was purchased
from C is 5) 0.46

The correct Match for LIST-I from LIST-II is
A B C D

• A. $4523$
• B. $5231$
• C. $2315$
• D. $1235$

Answer 1

The correct option is D $1235$

The probability of choosing A is 25% = $\frac{25}{100}=0.25$

The probability of choosing B is 45% = $\frac{45}{100}=0.45$

The probability of choosing C is 30% = $\frac{30}{100}=0.30$

The probability of A's defectives bulbs = 1% = 0.01
The probability of B's defectives bulbs = 1% = 0.01
The probability of C's defectives bulbs = 2% = 0.02
A) The probability of choosing A and purchasing a defective bulb from it is = $0.25\times 0.01=0.0025$ that is (1) in List II
B) The probability of choosing B and purchasing a defective bulb from it is = $0.45\times 0.01=0.0045$ that is (2) in List II
C) The probability of choosing C and purchasing a defective bulb from it is = $0.30\times 0.02=0.0060$ that is (3) in List II