An electrician charges $₹ 400$ per hour and spends $₹ 50$ a day, on kerosene Write an algebraic expression to represent his earnings for one day.

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Solution

Finding the algebraic expression
We have given,
Electrician charges for 1 hour $= ₹ 400$
Money spent on kerosene in one day $= ₹ 50$
Let the number of hours the electrician works be $x h o u r s$
Earnings for one day $= ₹ (400 x - 50)$
Hence, the algebraic expression of earnings is $₹ (400 x - 50)$

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An electrician charges ₹400 per hour and spends ₹50 a day, on kerosene Write an algebraic expression to represent his earnings for one day.

Finding the algebraic expressionWe have given,Electrician charges for 1 hour=₹400Money spent on kerosene in one day=₹50Let the number of hours the electrician works be xhoursEarnings for one day =₹400x-50Hence, the algebraic expression of earnings is ₹400x-50

An electrician charges $₹ 400$ per hour and spends $₹ 50$ a day, on kerosene Write an algebraic expression to represent his earnings for one day.