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Question

an electrolyte AB is 50% ionised in aqueous solution. Calculate the freezing point of 1 molal aqueous solution

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Solution

The electrolyte AB dissociates to AB A+ + B-Initialno of 1 0 0molesAt eqm 1- α α αi = 1-α +α +α = 1+α As α is 50 % ionised = 0.5so i = 1+0.5 = 1.5Tf = i Kf m = 1.5 × 1.86 × 1 = 2.79 0CTf - Tf(S) = 2.790 - 2.79 = Tf(S)Tf(S) = -2.79 0CThus the freezing point of solution =-2.79 0C

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