Question

An electromagnetic wave going through vacuum is described by $E=E_{0}sin(kx-\omega t);B=B_{0}sin(kx-\omega t)$. Which of the following equations is true?

• A. $E_{0}k=B_0\omega$
• B. $E_0\omega =B_{0}k$
• C. $E_0{B}_0=\omega k$
• D. None of these

Answer 1

The correct option is A $E_{0}k=B_0\omega$

$\frac{E_0}{B_0}=C$. also $k=\frac{2\pi }{\lambda }$ and $\omega =2\pi v$
These relation gives $E_{0}k=B_0\omega$