Question

An electromagnetic wave going through vacuum is described by $E=E_0\sin (kx-\omega t)$; $B=B_0\sin (kx-\omega t)$.
Which of the following equation is true?

• A. $E_{0}k=B_0\omega$
• B. $E_0\omega =B_{0}k$
• C. $E_0{B}_0=\omega k$
• D. None of the above

Answer 1

The correct option is A $E_{0}k=B_0\omega$

$\frac{E_0}{B_0}=c$, also $k=\frac{2\pi }{\lambda }$ and $\omega =2\pi v$.

$⟹\frac{E_0}{B_0}=\frac{\omega }{k}$

$E_{0}k=B_0\omega$.