Question

An electromagnetic wave, going through vacuum is described by $E=E_0\sin (kx-\omega t)$. Which of the following is independent of wavelength?

• A. $k$
• B. $\omega$
• C. $\frac{k}{\omega }$
• D. $k\omega$

Answer 1

The correct option is C $\frac{k}{\omega }$

$k=\frac{2\pi }{\lambda }$

$\omega =\frac{2\pi c}{\lambda },$where $c$ is the velocity of light

Hence, $\frac{k}{2\pi }=\frac{\omega }{2\pi c}⟹\frac{k}{\omega }$ is independent of the wavelength.