An electromagnetic wave passing through the space is given by equations $E = E_{o} sin (w t - k x), B = B_{0} sin (w t - k x)$ which of the following is true?

E_{o} B_{0} = w k

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E_{o} w = B_{o} k

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E_{o} k = B_{o} w

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E_{o} w k = B_{o}

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Solution

The correct option is C $E_{o} k = B_{o} w$
As $\frac{E_{o}}{B_{o}} = c$ (a)
where $c =$ speed of light
$c = ν λ$
Also
$w = 2 π ν$ (1)
$k = \frac{2 π}{λ}$ (2)
Dividing (2) by (1)
$\frac{w}{k} = \frac{2 π ν}{\frac{2 π}{λ}} = ν λ = c$
Hence (a) becomes
$\frac{E_{o}}{B_{o}} = \frac{w}{k}$
$E_{o} k = B_{o} w$
Hence the correct option is (C).

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An electromagnetic wave passing through the space is given by equations E=Eosin(wt−kx),B=B0sin(wt−kx) which of the following is true?

The correct option is C Eok=BowAs EoBo=c (a)where c=speed of lightc=νλAlsow=2πν (1)k=2πλ (2)Dividing (2) by (1)wk=2πν2πλ=νλ=c Hence (a) becomesEoBo=wkEok=BowHence the correct option is (C).

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