An electron, a proton and an alpha particle have KE of 16E, 4E and E respectively. What is the qualitative order of their de-Broglie wavelengths?

λ_{e} > λ_{p} = λ_{a}

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λ_{p} = λ_{a} > λ_{e}

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λ_{p} < λ_{e} < λ_{a}

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λ_{a} < λ_{e} \approx λ_{p}

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Solution

The correct option is A $λ_{e} > λ_{p} = λ_{a}$

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An electron, a proton and an alpha particle have KE of 16E, 4E and E respectively. What is the qualitative order of their de-Broglie wavelengths?

The correct option is A λe>λp=λa

The correct option is A $λ_{e} > λ_{p} = λ_{a}$