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Question

An electron accelerated by a potential difference of V volt posses a de Broglie wave length . If the accelerating potential is increased by a factor of 4, the de-Broglie wavelength of the electron will be

A
remains unchanged
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B
becomes double
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C
becomes half
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D
becomes 4 times
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Solution

The correct option is C becomes half
de-Broglie wavelength is given by λ=hp
where, momentum of the particle p=2mK
Kinetic energy of the particle K=eV
λ=h2meV
We get λ1V
Thus de-Broglie wavelength of the electron will become half if the accelerating potential is increased by a factor of 4.

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