An electron accelerated through a potential of 10-000 V from rest has a de-Broglie wave length - What should be the accelerating potential so that the wave length is doubled-

The correct option is D 5,000 V (10000)e=hc/λ ∴hc/2λ=(5000)e . ...

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Standard XII

Physics

Reflection from a Fixed End

An electron a...

Question

An electron accelerated through a potential of $10, 000 V$ from rest has a de-Broglie wave length $^{'} λ^{'}$ . What should be the accelerating potential so that the wave length is doubled?

20, 000 V

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40, 000 V

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5, 000 V

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2, 500 V

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Solution

The correct option is D $5, 000 V$
$(10000) e = \frac{h c}{λ}$
$∴ \frac{h c}{2 λ} = (5000) e$ .

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An electron accelerated through a potential of 10,000 V from rest has a de-Broglie wave length ′λ′. What should be the accelerating potential so that the wave length is doubled?

The correct option is D 5,000 V(10000)e=hcλ∴hc2λ=(5000)e.

An electron accelerated through a potential of $10, 000 V$ from rest has a de-Broglie wave length $^{'} λ^{'}$ . What should be the accelerating potential so that the wave length is doubled?

The correct option is D $5, 000 V$
$(10000) e = \frac{h c}{λ}$
$∴ \frac{h c}{2 λ} = (5000) e$ .