An electron and a photon have same wavelength. If p is the momentum of electron and E is the energy of photon, the magnitude of pE in SI unit will be :
A
3.0×108
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
3.33×10−9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
9.1×10−31
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
6.64×10−34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B3.33×10−9 From de Broglie wavelength formula λ=hp⇒p=hλ....(1)
And we know that energy of photon E=hv E=hcλ........(2) ∴ From equation (1) and (2), pE=hλ×λhc=1c pE=13×108=3.33×10−9