An electron and a proton are at a distance of $1$ A. The dipole moment of the system is :

3.2 \times 10^{- 29} C m

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1.6 \times 10^{- 19} C m

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1.6 \times 10^{- 29} C m

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3.2 \times 10^{- 19} C m

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Solution

The correct option is C $1.6 \times 10^{- 29} C m$
$1.3 \times 10^{- 29} C m$
$p = q \times 2 l = 1.6 \times 10^{- 19} \times (1 \times 10^{- 10})$
$= 1.6 \times 10^{- 29} C m$

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An electron and a proton are at a distance of 1 A. The dipole moment of the system is :

The correct option is C 1.6×10−29Cm1.3×10−29Cmp=q×2l=1.6×10−19×(1×10−10)=1.6×10−29Cm

An electron and a proton are at a distance of $1$ A. The dipole moment of the system is :

The correct option is C $1.6 \times 10^{- 29} C m$
$1.3 \times 10^{- 29} C m$
$p = q \times 2 l = 1.6 \times 10^{- 19} \times (1 \times 10^{- 10})$
$= 1.6 \times 10^{- 29} C m$