You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Thomson's Discovery of Electrons

An electron a...

Question

An electron and a proton are placed in a uniform electric field. The ratio of their acceleration will be :

zero

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m_{p} / m_{e}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

(one)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m_{e} / m_{p}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $m_{p} / m_{e}$
$a = \frac{F}{m} \Rightarrow \frac{a_{e}}{a_{p}} = \frac{F / m_{e}}{F / m_{p}} = \frac{m_{p}}{m_{e}}$

Suggest Corrections

Similar questions

Q. An electron of mass

m_{e}

and a proton of mass

m_{p}

, where

m_{p}

=

1836

m_{e}

are moving with the same speed . The ratio of their de Broglie wavelength i.e

\frac{λ_{electron}}{λ_{proton}}

will be :

Q. An electron and proton are accelerated through the same potential difference. The ratio of their de-Broglie wavelengths will be
[ Taking mp and me as mass' of proton and mass of electron ]

Q. An electron of mass

m_{e}

, and a proton of mass

m_{p}

are accelerated through the same potential. Then, the ratio of their de-Broglie wavelengths is

An electron of mass $m_{e}$ , initially at rest, moves through a certain distance in a uniform electric field in time $t_{1}$ . A proton of mass $m_{p}$ , also initially at rest, takes time $t_{2}$ to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio $\frac{t_{2}}{t_{1}}$ is nearly equal to,

Q. An electron of mass

m_{e}

initially at rest moves through a certain distance in a uniform electric field in time

t_{1}

. A proton of mass

m_{p}

, also initially at rest, takes time

t_{2}

to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio

\frac{t_{2}}{t_{1}}

is nearly equal to

Join BYJU'S Learning Program

An electron and a proton are placed in a uniform electric field. The ratio of their acceleration will be :

The correct option is A mp/mea=Fm⇒aeap=F/meF/mp=mpme

The correct option is A $m_{p} / m_{e}$
$a = \frac{F}{m} \Rightarrow \frac{a_{e}}{a_{p}} = \frac{F / m_{e}}{F / m_{p}} = \frac{m_{p}}{m_{e}}$