An electron and a proton of equal kinetic energy enter a uniform magnetic field normal to the lines of force. The radii of curvature of the circular paths be :
A
rerp=11
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B
rerp=mpme
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C
rerp=√mpme
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D
rerp=√memp
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Solution
The correct option is Drerp=√memp Radius in magnetic field is given by, r=mvqB=√2mEqB where E=p22m ∴rerp=m1/2eqem1/2pqp=√memp