An electron at rest is accelerated through a potential difference of 200 V. If the electron acquires a velocity $8.4 \times 10^{6} m / s$ , the value of e/m of electron is

2.76 \times 10^{12} C / k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.76 \times 10^{11} C / k g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.76 \times 10^{12} C / k g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

N o n e o f t h e s e

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.76 \times 10^{12} C / k g$
During acceleration through the potential difference, the electron acqiures some kinetic energy.
$∴$ $\frac{1}{2} m v^{2} = e V$
or $\frac{e}{m} = \frac{v^{2}}{2 V} = \frac{(8.4 \times 10^{6})^{2}}{2 \times 200}$
$⟹ \frac{e}{m} = 1.76 \times 10^{11} C / k g$

Suggest Corrections

Similar questions

Q. An electron is accelerated through a potential difference of

200 V

. If e/m for the electron be

1.6 \times 10^{11}

coulomb

k g^{- 1}

, then the velocity acquired by the electron will be

Q. An electron at rest is accelerated through the potential difference applied across anode and cathode of 200V. If the velocity of the electron is

8.4 \times 10^{6} m / s

. Then its specific charge is

Q. In a Thomson set-up for the determination of e/m, electrons accelerated by 2.5 kV enter the region of crossed electric and magnetic fields of strengths

3.6 \times 10^{4} V M^{- 1}

and

1.2 \times 10^{- 3} T

respectively and go through undeflected. The measured value of e/m of the electron is equal to

An electron of mass $M k g$ and charge $e c o u l o m b$ travels from rest through a potential difference of $V v o l t$ . The final velocity of the electron is $(i n m / s)$ :

Q. An electron moves with a velocity

1 \times 10^{3} m / s

in a magnetic field of induction

0.3 T

at an angle

30^{o}

. If

\frac{e}{m}

of electrons

1.76 \times 10^{11} C / k g

, the radius of the path is nearly

Join BYJU'S Learning Program

An electron at rest is accelerated through a potential difference of 200 V. If the electron acquires a velocity 8.4×106m/s, the value of e/m of electron is

The correct option is C 0.76×1012C/kgDuring acceleration through the potential difference, the electron acqiures some kinetic energy.∴ 12mv2=eV or em=v22V=(8.4×106)22×200⟹ em=1.76×1011C/kg

An electron at rest is accelerated through a potential difference of 200 V. If the electron acquires a velocity $8.4 \times 10^{6} m / s$ , the value of e/m of electron is