Question

An electron beam of energy 10 KeV is incident on metallic foil. If the interatomic distance is 0.55Å. Find the angle of diffraction.

• A. $si{n}^{-1}\left(0.11\right)$
• B. $si{n}^{-1}\left(0.22\right)$
• C. $co{s}^{-1}\left(0.11\right)$
• D. $co{s}^{-1}\left(0.22\right)$

Answer 1

The correct option is B $si{n}^{-1}\left(0.22\right)$

$\lambda =Dsin\varphi \Rightarrow \frac{12.27}{\sqrt{v}}\stackrel{\circ }{A}=Dsin\varphi \Rightarrow \frac{12.27\times {10}^{-10}}{\sqrt{10\times {10}^3}}=0.55\times {10}^{-10}sin\varphi \varphi =si{n}^{-1}\left(0.223\right)$