Question

An electron beam passes through a transverse magnetic field of $2\times {10}^{-3}$ tesla and electric field $E$ of $3.4\times {10}^{4}V/m$ acting simultaneously. If the path of the electrons remain undeviated, calculate the speed of the electrons

Answer 1

Data:
Strength of magnetic field $\left(B\right)=2\times {10}^{-3}Tesla$
Strength of electric field $\left(E\right)=3.4\times {10}^{4}V/m$
Speed of electron $V=\frac{E}{B}$
$=\frac{3.4\times {10}^4}{2\times {10}^{-3}}=1.7\times {10}^{7}m{s}^{-1}$.