An electron (charge = $1.6 \times 10^{- 19} C$ is accelerated through a potential of 100,000 V. The energy acquired by the electron is

$1.6 \times 10^{- 24} J$

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$1.6 \times 10^{- 14} e r g$

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0.53 \times 10^{- 17} J

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1.6 \times 10^{- 14} J

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Solution

The correct option is D $1.6 \times 10^{- 14} J$
$E = e V = 1.6 \times 10^{- 19} \times 10^{5} = 1.6 \times 10^{- 14} J$

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An electron (charge = 1.6×10−19C is accelerated through a potential of 100,000 V. The energy acquired by the electron is

The correct option is D 1.6×10−14JE=eV=1.6×10−19×105=1.6×10−14J

An electron (charge = $1.6 \times 10^{- 19} C$ is accelerated through a potential of 100,000 V. The energy acquired by the electron is

The correct option is D $1.6 \times 10^{- 14} J$
$E = e V = 1.6 \times 10^{- 19} \times 10^{5} = 1.6 \times 10^{- 14} J$