An electron (charge = $1.6 \times 10^{- 19}$ coulomb) is accelerated through a potential of 1,00,000 volts. The energy required by the electron is

1.6 \times 10^{- 24}

joule

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.6 \times 10^{- 14}

joule

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.53 \times 10^{- 14}

joule

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.6 \times 10^{- 14}

joule

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $1.6 \times 10^{- 14}$ joule
Energy = qV= $1.6 \times 10^{- 19} \times 100000 = 1.6 \times 10^{- 14} J$

Suggest Corrections

Similar questions

Q. An electron (charge =

1.6 \times 10^{- 19} C

is accelerated through a potential of 100,000 V. The energy acquired by the electron is

$1.6 \times 10^{- 24} J$

$1.6 \times 10^{- 14} e r g$

0.53 \times 10^{- 17} J

1.6 \times 10^{- 14} J

Q. An electron of mass

9.1 \times 10^{- 31}

kg and charge

1.6 \times 10^{- 19}

C is accelerated through a potential difference of 'V' volt. The de Broglie wavelength

(λ)

associated with the electron is

An electron is accelerated through a potential difference of $200$ volts. If $\frac{e}{m}$ ratio for the electron be $1.6 \times 10^{11}$ coulomb/kg, the velocity acquired by the electron will be :

An electron initially at rest is accelerated through a potential difference of 1 V. The energy gained by the electron is:

Q. Calculate the kinetic energy in electron volt of a charge of 8 x10

^{- 19}

C when it is accelerated through a potential difference of 200 V:

Join BYJU'S Learning Program

An electron (charge = 1.6×10−19 coulomb) is accelerated through a potential of 1,00,000 volts. The energy required by the electron is

The correct option is D 1.6×10−14 jouleEnergy = qV= 1.6×10−19×100000=1.6×10−14J

An electron (charge = $1.6 \times 10^{- 19}$ coulomb) is accelerated through a potential of 1,00,000 volts. The energy required by the electron is

The correct option is D $1.6 \times 10^{- 14}$ joule
Energy = qV= $1.6 \times 10^{- 19} \times 100000 = 1.6 \times 10^{- 14} J$