An electron collides with a hydrogen atom in its ground state and excites it to $n = 3$ . The energy given to hydrogen atom in this inelastic collision is
[Neglect the recoiling of hydrogen atom]

10.2 eV

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12.1 eV

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12.5 eV

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None of these

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Solution

The correct option is B $12.1 eV$
The energy required for electron for its transition from $n = 1$ to $n = 3$ state.

$Δ E$ (given to hydrogen atom)

$Δ E = E_{0}$ $(\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$

$Δ E = 13.6 (1 - \frac{1}{9}) = 13.6 \times \frac{8}{9} = 12.1 eV$

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An electron collides with a hydrogen atom in its ground state and excites it to n=3. The energy given to hydrogen atom in this inelastic collision is [Neglect the recoiling of hydrogen atom]

The correct option is B 12.1 eVThe energy required for electron for its transition from n=1 to n=3 state. ΔE (given to hydrogen atom) ΔE=E0(1n21−1n22) ΔE=13.6(1−19)=13.6×89=12.1 eV

An electron collides with a hydrogen atom in its ground state and excites it to $n = 3$ . The energy given to hydrogen atom in this inelastic collision is
[Neglect the recoiling of hydrogen atom]

The correct option is B $12.1 eV$
The energy required for electron for its transition from $n = 1$ to $n = 3$ state.

$Δ E$ (given to hydrogen atom)

$Δ E = E_{0}$ $(\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}})$

$Δ E = 13.6 (1 - \frac{1}{9}) = 13.6 \times \frac{8}{9} = 12.1 eV$