An electron enters an electric field with its velocity in the direction of the electric lines of force then

the path of the electron will be a circle

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the path of the electron will be a parabola

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the velocity of the electron will decrease

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the velocity of the electron will increase

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Solution

The correct option is C the velocity of the electron will decrease
An electron enters an electric field $(E)$ with its velocity in the direction of the electric lines of force then.
$V = \sqrt{\frac{2 q}{E}}$
$E$ $α$ $\frac{1}{V^{2}}$
Hence the velocity of the electron will decrease.

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D) the electrons velocity will decrease in magnitude

Ans given is option D

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An electron enters an electric field with its velocity in the direction of the electric lines of force then

The correct option is C the velocity of the electron will decreaseAn electron enters an electric field (E) with its velocity in the direction of the electric lines of force then.V=√2qEE α 1V2Hence the velocity of the electron will decrease.

The correct option is C the velocity of the electron will decrease
An electron enters an electric field $(E)$ with its velocity in the direction of the electric lines of force then.
$V = \sqrt{\frac{2 q}{E}}$
$E$ $α$ $\frac{1}{V^{2}}$
Hence the velocity of the electron will decrease.