An electron enters into a magnetic field of induction 1×10−2T with velocity 1×107m/s and deflects into a circular path of radius 6×10−3m. The specific charge of the electron is :
A
2.4×1011Ckg−1
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B
1.67×1011Ckg−1
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C
3.2×1011Ckg−1
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D
0.8×1011Ckg−1
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Solution
The correct option is B1.67×1011Ckg−1 Let the e/m of electron be L Centripetal force =mv2r -------------------------(I) Force provided by the magnetic field =qBv ----------------------(II) Equating (I) and (II), mv2r=Bqv mvr=Bq⇒vBr=em ⇒L=vBr=10710−2×6×10−3 ⇒L=1.667×1011Ckg−1