Question

# An electron falls from rest through a vertical distance h in a uniform and vertically upward directed electric field E. The direction of electric field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in it through the same vertical distance h. The time of fall of the electron as compared to the time of fall of the proton is

A
10 times greater
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B
smaller
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C
equal
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D
5 times greater
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Solution

## The correct option is B smaller For electron:- meg+Fe=mea a=meg+eEme ae=g+emeE Now, h=12aet2 te=  ⎷2hg+eEme For proton: mpg+Fe=mpa ap=g+eEmp Now, h=12×apt2 ⇒tp=  ⎷2hg+eEmp ∵mp>me te<tp

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