An electron flies into a homogeneous magnetic field perpendicular to the lines of force- The velocity of electron is 4 - 107 ms -1 and induction of fieldis 10-3 T- The tangential and normal accelerations of electron areA- 0-7 - 1015 ms -2B- 7 - 1015 ms -2- 0C- 5 - 1015 ms -2- 0D- 3 - 1015 ms -2- 0

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Desciption of Force

An electron f...

Question

An electron flies into a homogeneous magnetic field perpendicular to the lines of force. The velocity of electron is $4 \times 10^{7} m s^{- 1}$ and induction of field is $10^{- 3}$ T. The tangential and normal accelerations of electron are

7 \times 10^{15} m s^{- 2}, 0

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5 \times 10^{15} m s^{- 2}, 0

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3 \times 10^{15} m s^{- 2}, 0

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0, 7 \times 10^{15} m s^{- 2}

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Solution

The correct option is D $0, 7 \times 10^{15} m s^{- 2}$
Tangential acceleration = 0
Normal acceleration
ma = Bqv
$a = \frac{B q v}{m} a = \frac{10^{- 3} \times 1.6 \times 10^{- 19} \times 4 \times 10^{7}}{9.1 \times 10^{- 31}} = \frac{64}{9} \times 10^{15} = 7 \times 10^{15} m s^{- 2}$

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An electron flies into a homogeneous magnetic field perpendicular to the lines of force. The velocity of electron is 4×107ms−1 and induction of field is 10−3T. The tangential and normal accelerations of electron are

The correct option is D 0,7×1015ms−2 Tangential acceleration = 0 Normal acceleration ma = Bqv a=Bqvma=10−3×1.6×10−19×4×1079.1×10−31=649×1015=7×1015ms−2

An electron flies into a homogeneous magnetic field perpendicular to the lines of force. The velocity of electron is $4 \times 10^{7} m s^{- 1}$ and induction of field is $10^{- 3}$ T. The tangential and normal accelerations of electron are

The correct option is D $0, 7 \times 10^{15} m s^{- 2}$
Tangential acceleration = 0
Normal acceleration
ma = Bqv
$a = \frac{B q v}{m} a = \frac{10^{- 3} \times 1.6 \times 10^{- 19} \times 4 \times 10^{7}}{9.1 \times 10^{- 31}} = \frac{64}{9} \times 10^{15} = 7 \times 10^{15} m s^{- 2}$