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Question

An electron flies into a homogeneous magnetic field perpendicular to the lines of force. The velocity of electron is 4×107ms1 and induction of field is 103T. The tangential and normal accelerations of electron are

A
7×1015ms2,0
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B
5×1015ms2,0
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C
3×1015ms2,0
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D
0,7×1015ms2
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Solution

The correct option is D 0,7×1015ms2
Tangential acceleration = 0
Normal acceleration
ma = Bqv
a=Bqvma=103×1.6×1019×4×1079.1×1031=649×1015=7×1015ms2

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