An electron flies into a homogeneous magnetic field perpendicular to the lines of force. The velocity of electron is 4×107ms−1 and induction of field is 10−3T. The tangential and normal accelerations of electron are
A
7×1015ms−2,0
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B
5×1015ms−2,0
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C
3×1015ms−2,0
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D
0,7×1015ms−2
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Solution
The correct option is D0,7×1015ms−2 Tangential acceleration = 0
Normal acceleration
ma = Bqv a=Bqvma=10−3×1.6×10−19×4×1079.1×10−31=649×1015=7×1015ms−2