An electron has a constant acceleration of $3.2 m / s^{2}$ . At a certain instant its velocity is $9.6 m / s$ . What is its velocity $2.5$ second earlier.

1.6 m / s

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3.2 m / s

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0.8 m / s

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4.8 m / s

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Solution

The correct option is A $1.6 m / s$
$a = 3.2 m / s^{2}$
$v = 9.6 m / s$
$u = ?$
$t = 2.5 s$
As we know, $v = u + a t$
or, $u = v - a t$
$= 9.6 - 3.2 \times 2.5$
$= 1.6 m / s$

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