An electron has a speed of 100 m/s with an accuracy of 0.005%. The uncertainty in position will be

0.14 m

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1.4 m

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0.014 m

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14.0 m

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Solution

The correct option is A 0.14 m
Speed of electron $v = 100 m / s$
Uncertainty in speed $Δ v = 0.00005 \times 100 = 0.005 m / s$
Uncertainty in position $Δ x = \frac{h}{m Δ v}$
$⟹ Δ x = \frac{6.626 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 0.005} = 0.14 m$

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An electron has a speed of 100 m/s with an accuracy of 0.005%. The uncertainty in position will be

The correct option is A 0.14 mSpeed of electron v=100 m/sUncertainty in speed Δv=0.00005×100=0.005 m/sUncertainty in position Δx=hmΔv⟹ Δx=6.626×10−349.1×10−31×0.005=0.14 m

The correct option is A 0.14 m
Speed of electron $v = 100 m / s$
Uncertainty in speed $Δ v = 0.00005 \times 100 = 0.005 m / s$
Uncertainty in position $Δ x = \frac{h}{m Δ v}$
$⟹ Δ x = \frac{6.626 \times 10^{- 34}}{9.1 \times 10^{- 31} \times 0.005} = 0.14 m$