Question

An electron has kinectic energy 2.8*10^-23 j find de Broglie wavelength is

Answer 1

Let Mass of the electron is 9.1 × 10⁻³¹ kg.

K = 2.8 × 10⁻²³ J.


Since,

K = 1/2 × m × v²

⇒ 2.8 × 10⁻²³ = 1/2 × 9.1 × 10⁻³¹ × v²

⇒ v² = 0.615 × 10⁸

∴ v = 0.78 × 10⁴



Using the Formula,

λ = h/mv

⇒ λ = 6.62 × 10⁻³⁴/(9.1 × 10⁻³¹ × 0.78 × 10⁴)

∴ λ = 0.93 × 10⁻⁷ m.



Hence, the de-broglie wavelength of the Electron is 0.93 × 10⁻⁷ m