You visited us 6 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Energy Levels

An electron h...

Question

An electron has wavelength $1 A^{o}$ . The potential by which the electron is accelerated will be:

0.0926 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0502 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.0826 V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

51.2 V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $0.0826 V$
If electron is accelerated by V volt,
$K . E = e V = \frac{1}{2} m v^{2}$
$λ = \frac{h}{m v}$
$λ = \frac{h}{\sqrt{2 e V m}}; λ = 1 A^{o}$
On solving, $V = 0.0826 V$

Suggest Corrections

Similar questions

The de-Broglie wavelength of an electron, accelerated by potential V is $λ$ . What will be the de-Broglie wavelength of the electron which is accelerated by 4V potential?

Q. An electron wave has wavelength

1 ˚ A

. Calculate the potential with which the electron is accelerated.

Q. An electron is accelerated through a potential difference of

V

volt. It has a wavelength

λ

associated with it. Through what potential difference an electron must be accelerated so that its de Broglie wavelengths is the same as that of a proton? Take mass of proton to be

1837

times larger than the mass of electron

Q. An electron is accelerated through a potential difference of

10000 V

. The de Broglie wavelength associated with electron will be

Q. An electron acelerated under a potential difference of

V (in V)

has a certain wavelength

λ .

Mass of the proton is

2000

times the mass of an electron. If the proton has to have the same wavelength

λ

, then it will have to be accelerated under potential difference of

(in V)

Join BYJU'S Learning Program

An electron has wavelength 1Ao. The potential by which the electron is accelerated will be:

The correct option is C 0.0826VIf electron is accelerated by V volt,K.E=eV=12mv2λ=hmvλ=h√2eVm;λ=1AoOn solving, V=0.0826V

An electron has wavelength $1 A^{o}$ . The potential by which the electron is accelerated will be:

The correct option is C $0.0826 V$
If electron is accelerated by V volt,
$K . E = e V = \frac{1}{2} m v^{2}$
$λ = \frac{h}{m v}$
$λ = \frac{h}{\sqrt{2 e V m}}; λ = 1 A^{o}$
On solving, $V = 0.0826 V$