Question

An electron hole pair is formed when light of maximum wavelength $6000\dot{\text{A}}$ is incident on the semiconductor. The band gap energy of the semiconductor is $1.65k\times {10}^{-19}\text{J}$. The value of $k$ .(Integer only) $h=6.62\times {10}^{-34}\text{Js}$

Answer 1

Band energy gap,

$E=\frac{hc}{\lambda }$

$\Rightarrow E=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{6000\times {10}^{-10}}$

$\Rightarrow E=3.3\times {10}^{-19}\text{J}$

Given, $E=1.65k\times {10}^{-19}\text{J}$

$\therefore k=2$