An electron in a Bohr orbit of hydrogen atom with the quantum number n2 has an angular momentum 4.2176×10−34 kg m2s−1. If electron drops from this level to the next level. Find the wavelength of this line?
A
18.75×10−7 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1.87×10−7 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
187.5×10−7 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.188×10−7 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D0.188×10−7 m According to Bohr's atomic model
mvr = nh/2 π 4.2176×10−34=n2×6.62×10−342×3.14 n2=4
So, if n2 = 4, electrons is deexcited, so n1 = 3 1λ=RZ2×[132−142]
where Z = Atomic number
On solving, λ=18.787×10−7 m