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Standard XII

Physics

Characteristics of Bohr's Atomic Model

An electron i...

Question

An electron in a hydrogen atom makes a transition from $n = n_{1}$ to $n = n_{2}$ . The time period of the electron in the initial state is eight times that in the final state. The possible values of $n_{1}$ and $n_{2}$ are

n_{1} = 4, n_{2} = 2

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n_{1} = 8, n_{2} = 2

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n_{1} = 8, n_{2} = 1

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n_{1} = 6, n_{2} = 4

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Solution

The correct option is A $n_{1} = 4, n_{2} = 2$
As $T^{2} \propto R^{3}$
we get $\frac{R_{1}}{R_{2}} = 4$

As, $\frac{R_{1}}{R_{2}} = \frac{n_{1}^{2}}{n_{2}^{2}}$
$\Rightarrow \frac{n_{1}}{n_{2}} = 2$

The possible values from the given options is $n_{1} = 4, n_{2} = 2$

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An electron in a hydrogen atom makes a transition from n=n1 to n=n2. The time period of the electron in the initial state is eight times that in the final state. The possible values of n1 and n2 are

The correct option is A n1=4, n2=2As T2∝R3 we get R1R2=4 As, R1R2=n21n22 ⇒n1n2=2 The possible values from the given options is n1=4, n2=2

An electron in a hydrogen atom makes a transition from $n = n_{1}$ to $n = n_{2}$ . The time period of the electron in the initial state is eight times that in the final state. The possible values of $n_{1}$ and $n_{2}$ are

The correct option is A $n_{1} = 4, n_{2} = 2$
As $T^{2} \propto R^{3}$
we get $\frac{R_{1}}{R_{2}} = 4$

As, $\frac{R_{1}}{R_{2}} = \frac{n_{1}^{2}}{n_{2}^{2}}$
$\Rightarrow \frac{n_{1}}{n_{2}} = 2$

The possible values from the given options is $n_{1} = 4, n_{2} = 2$