Question

# An electron in ground state absorbs 1.5 times as much energy required to  escape from H atom. The wavelength of   electron emitted in A$$^{o}$$ is :

A
4.21
B
4.71
C
3.52
D
3.711

Solution

## The correct option is B 4.71 IE of H atom = 13.6 eVIncident energy = 1.5 $$\times$$ IE = 1.5 $$\times$$ 13.6 eVKE of e$$^-$$ ejected out = (1.5 $$\times$$ 13.6) - 13.6 = 0.5 $$\times$$ 13.6E$$_k$$ = 0.5 $$\times$$ 13.6 eV = 6.8 $$\times$$ 1.6 $$\times$$ 10$$^{-19}$$ J$$\lambda$$ = $$\displaystyle\frac{h}{\sqrt{2 Em}}$$ = $$\displaystyle\frac{6.62 \times 10^{-34} J s}{(2 \times 6.8 \times 9.1 \times 10^{-31} kg \times 1.6 \times 10^{-19})^{1/2}}$$= $$\displaystyle\frac{6.62 \times 10^{-9}}{14.07}$$$$\lambda$$ = $$4.71 A^o$$Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More