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Question

An electron in ground state absorbs 1.5 times as much energy required to  escape from H atom. The wavelength of   electron emitted in A$$^{o}$$ is :


A
4.21 
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B
4.71 
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C
3.52 
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D
3.711 
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Solution

The correct option is B 4.71 
IE of H atom = 13.6 eV
Incident energy = 1.5 $$\times$$ IE = 1.5 $$\times$$ 13.6 eV
KE of e$$^-$$ ejected out = (1.5 $$\times$$ 13.6) - 13.6 = 0.5 $$\times$$ 13.6
E$$_k$$ = 0.5 $$\times$$ 13.6 eV = 6.8 $$\times$$ 1.6 $$\times$$ 10$$^{-19}$$ J
$$\lambda$$ = $$\displaystyle\frac{h}{\sqrt{2 Em}}$$ = $$\displaystyle\frac{6.62 \times 10^{-34} J s}{(2 \times 6.8 \times 9.1 \times 10^{-31} kg \times 1.6 \times 10^{-19})^{1/2}}$$
= $$\displaystyle\frac{6.62 \times 10^{-9}}{14.07}$$
$$\lambda$$ = $$4.71 A^o$$

Chemistry

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