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Question

An electron in Hatom is in its ground state absorbs 1.50 times as much as energy as the minimum required for its escape [13.6 eV] from the atom. Thus KE given to emitter electron is

A
13.6 eV
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B
20.4 eV
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C
34.0 eV
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D
6.8 eV
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Solution

The correct option is D 6.8 eV
The ionization energy of hydrogen atom (ϕ)=13.6eV

Energy absorbed by hydrogen atom (E)=13.6×1.5=20.4eV

Kinetic Energy (KE)=EΦ=20.413.6=6.8eV

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