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1900's Physics and Wave

An electron i...

Question

An electron in $H - a t o m$ is in its ground state absorbs $1.50$ times as much as energy as the minimum required for its escape $[13.6 e V]$ from the atom. Thus $K E$ given to emitter electron is

13.6 e V

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20.4 e V

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34.0 e V

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6.8 e V

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Solution

The correct option is D $6.8 e V$
The ionization energy of hydrogen atom $(ϕ) = 13.6 e V$

Energy absorbed by hydrogen atom $(E) = 13.6 \times 1.5 = 20.4 e V$

Kinetic Energy $(K E) = E - Φ = 20.4 - 13.6 = 6.8 e V$

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(m_{e} = 9.1 \times 10^{- 31} k g, h = 6.626 \times 10^{- 34} J s)

(m_{e} = 9.109 \times 10^{- 31} k g, e = 1.602 \times 10^{- 19}

h = 6.63 \times 10^{- 34} J . s)

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