Question

an electron in hydrogen atom makes a transition from n=5 to n=1. find max. no of photons emitted

Answer 1

Dear Student,

we can find the wavelength of photon

$$\begin{gathered} \frac{1}{\lambda }=1.1*{10}^7\left(\frac{1}{n^2}-\frac{1}{m2}\right) \\ n=1,m=5 \\ \frac{1}{\lambda }=1.1*{10}^7\times 0.96 \\ \lambda =0.95*{10}^{-7}m \\ Regards \end{gathered}$$


$$\begin{gathered} \frac{1}{\lambda }=1.1*{10}^7\left(\frac{1}{n^2}-\frac{1}{m^2}\right) \\ n=1,m=5 \\ \frac{1}{\lambda }=1.1*{10}^7\left(\frac{1}{1}-\frac{1}{25}\right)=1.1*{10}^7\left(1-0.04\right)=1.056*{10}^7 \\ \lambda =0.95*{10}^{-7}mwavelengthofthephoton \\ Regards \end{gathered}$$