Question

An electron in the hydrogen atom is excited from $1^{st}$ orbit to $5^{th}$ orbit. Find the change in energy of the electron in eV:

• A. (13.6 x 24) / 25
• B. (13.6 x 4) / 5
• C. (0.529 x 4) / 5
• D. (13.6 x 4) / 9

Answer 1

The correct option is A (13.6 x 24) / 25

$E=-13.6\frac{z^2}{n^2}eV\therefore E_1=-13.6eV$

and $E_5=-13.6\times \frac{1}{25}eV$

$\therefore \Delta E=E_5-E_1=(\frac{24}{25}\times 13.6)eV$

Hence answer is option A