Question

An electron is accelerated from rest through a P.D. of 1600 volt. Find the velocity acquired by the electron. Mass of electron = $9.1\times {10}^{-31}kg.$

Answer 1

$E=qV=eV=1600ev$

$E=\frac{1}{2}m{v}^2$

$⟹v=\sqrt{\frac{2E}{m}}$

$⟹v=\sqrt{\frac{2\times 1600\times 1.6\times {10}^{-19}}{9.1\times {10}^{-31}}}$

$⟹v=2.37\times {10}^{7}m/s$