An electron is accelerated under a potential difference of 182 V. The maximum velocity of electron will be (charge of electron is 1.6×10−19Cand its mass is9.1×10−31kg)
A
800ms−1
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B
8×106ms−1
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C
4×103ms−1
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D
4×106ms−1
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Solution
The correct option is B8×106ms−1 12mv2=eV⇒v=√2×1.6×10−19×1829.1×10−31=8×106ms−1