CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An electron is constrained to move along the yaxis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E=30^jsin(1.5×107t5×102x) V/m. The maximum magnetic force experienced by the electron will be

(given c=3×108 ms1 & electron charge =1.6×1019 C)

A
3.2×1018 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.4×1018 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
4.8×1019 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
1.6×1019 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 4.8×1019 N
In electromagnetic wave,
E0B0=c
Maximum value of magnetic field, B0=E0c
Maximum magnetic force is
Fmax=qVBmaxsin90°=qV0E0c
(Given V0=0.1 c and E0=30 V/m)
Fmax=1.6×1019×0.1×3×108×303×108=4.8×1019 N

flag
Suggest Corrections
thumbs-up
10
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Direction of Induced Current
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon