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Question

# An electron is moving along +x direction with a velocity of 6×106 ms−1. It enters a region of uniform electric feild of 300 V/cm pointing along +y direction of the magnetic feild set up in this region such that electron keeps moving along the +x direction will be:

A
3×104 T, along +z direction
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B
5×103 T, along z direction
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C
5×103 T, along +z direction
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D
3×104 T,, along z direction
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Solution

## The correct option is C 5×10−3 T, along +z directionGiven: →E=300^j V/cm=3×104 V/m →v=6×106^i m/s →B must be in +z axis. So, q→E+q→v×→B=0 ⇒ E=vB ∴B=Ev=3×1046×106=5×10−3 T Hence, magnetic field B=5×10−3 T along +z direction.

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