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Question

An electron is moving in a circular path of radius 5.1×1011 m at a frequency of 6.8×1015 revolutions/sec. The equivalent current is approximately equal to _______.
  1. 5.1×103A
  2. 1.1×103A
  3. 6.8×103A
  4. 2.2×103A


Solution

The correct option is B 1.1×103A
Given:
Frequency, v=6.8×1015 rev/s,
Time, T=1frequency=16.8×1015s
Current is given by:
i=QT=1.6×1019×6.8×1015
=1.1×103A.

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