Question

# An electron is moving in a circular path of radius 5.1×10−11 m at a frequency of 6.8×1015 revolutions/sec. The equivalent current is approximately equal to _______.5.1×10−3A1.1×10−3A6.8×10−3A2.2×10−3A

Solution

## The correct option is B 1.1×10−3AGiven: Frequency, v=6.8×1015 rev/s, Time, T=1frequency=16.8×1015s Current is given by: i=QT=1.6×10−19×6.8×1015 =1.1×10−3A.

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