wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

An electron is moving with an initial velocity ¯v=v0^i and is in a magnetic field ¯B=B0^j then its de Broglie wavelength

A
remains constant
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
increases with time
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
decreases with time
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
increases and decreases periodically
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B remains constant

The magnetic force on moving electron is given as,

F=e(v0i×B0j)

=ev0B0k

Since the force is perpendicular to v and B, so the magnitude of v will not change that’s means the momentum will remain constant.

De Broglie wavelength is given as,

λ=hmv

Thus, if the momentum will remain constant, then de Broglie wavelength will remain constant.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Magnetic Force
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon