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Question

An electron is moving with velocity (2^i+2^j)m/s in an electric field of intensity E=^i+2^j8^kvolt/m and a magnetic field of B=(2^j+3^k) tesla. Find the magnitude of force on the electron.

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Solution

Force acting on electron
F=q(E+v×B)v×B=∣ ∣ ∣^i^j^k220023∣ ∣ ∣=^i(60)^j(60)+^k(40)=(6^i6^j+4^k)F=1.6×1019[(^i+2^j8^k)+(6^i6^j+4^k)]=1.6×1019(7^i4^j4^k)|F|=1.6×1019×(7)2+(4)2+(4)2=1.6×1019×9=14.4×1019N

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