An electron is revolving in a circular path of radius 2-0- 10-10 m with a uniform speed of 3- 106 m-s- The magnetic induction at the centre of the circular path will be

An electron with a speed of 1.8 x 10⁶m/s is moving in a circular orbit in a uniform magnetic field of 10^-4Wb/m², the radius of the circular path of the electron is

Q. In Bohr atomic model an electron is revolving round the nucleus in a circular path of radius

5.1 \times 10^{- 11}

m

with a frequency

6.8 \times 10^{15}

cycles/sec. The magnetic induction at the center of the orbit will be :
(Given charge on electron

e = 1.6 \times 10^{- 19} C

)

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An electron is revolving in a circular path of radius 2.0×10−10 m with a uniform speed of 3×106m/s. The magnetic induction at the centre of the circular path will be

The correct option is B 1.2TCurrent in the circular orbit: i=qv2πrMagnetic field at the center of a circular coil is B=μ0i2r=4π×10−7qv2πr2r=10−7×qvr2=10−71.6×10−19×3×10622×10−20=1.2T

An electron is revolving in a circular path of radius $2.0 \times 10^{- 10}$ m with a uniform speed of $3 \times 10^{6} m / s$ . The magnetic induction at the centre of the circular path will be