Question

An electron is sent in an electric field of intensity ${10}^6$ V/m. If the weight of electron is negligible, its acceleration will be

• A. $1.7\times {10}^{18}m/s^2$
• B. $1.7\times {10}^{17}m/s^2$
• C. $1.7\times {10}^{21}m/s^2$
• D. $1.7\times {10}^{25}m/s^2$

Answer 1

The correct option is B $1.7\times {10}^{17}m/s^2$

We know that,
F = eE or ma = eE or $a=\frac{eE}{m}$
$\therefore a=\frac{(1.6\times {10}^{-19})\left({10}^6\right)}{9.1\times {10}^{-31}}=1.7\times {10}^{17}m{s}^{-2}$